Hi Brian,
On Fri, 2003-02-07 at 03:15, [EMAIL PROTECTED] wrote:
> void do_real_exit(int ID, void *data)
> {
> int status;
>
> /* Kill all our children and exit */
>
> printf("real exit here\n");
> kill(0,9);
> waitpid(pid,&status,0);
> exit(0);
> }
>
> void Exit_cb(GtkWidget *ob, long data)
> {
> /* Try to exit gracefully, wait 1 second, do real exit */
>
> write(out_pipe,"q\n\n\n",4);
> gtk_timeout_add(2000,(GtkFunction)do_real_exit,0);
> }
>
>
> Is the kill(0,9) really necessary? Surely, if it is, then there is a
> bug in lavplay, no?
it writes q\n, which quits lavplay nicely. After that, lavplay should be
long gone when do_real_exit() is called. If not, then something is
surely wrong and we'd better kill lavplay as evilly as possible to
prevent zombie processes, so we kill -9 it.
Normally, the kill -9 won't do anything because there won't be any open
child processes. I'd call this "not a bug, but a feature".
Ronald
--
Ronald Bultje <[EMAIL PROTECTED]>
Linux Video/Multimedia developer
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