> Am a bit confused by the output of the this C program:
>
> -------------------------------------------------------------ptr.c---
> #include <stdio.h>
>
> int
> main()
> {
> int *ptr, x;
>
> x = 2;
> ptr = &x;
>
> printf("x=%d, *ptr=%d, ptr=%p, &x=%p\n", x, *ptr, ptr, &x);
>
> *ptr++;
> printf("x=%d, *ptr=%d, ptr=%p, &x=%p\n", x, *ptr, ptr, &x);
>
> ++(*ptr);
> printf("x=%d, *ptr=%d, ptr=%p, &x=%p\n", x, *ptr, ptr, &x);
>
> return 0;
> }
>
> --------------------------------------------------------------------------
>
> The output I get is this:
>
> $ ./a.out
> x=2, *ptr=2, ptr=0xbfbfece0, &x=0xbfbfece0
> x=2, *ptr=-1077941020, ptr=0xbfbfece4, &x=0xbfbfece0
> x=2, *ptr=750764012, ptr=0xbfbfece5, &x=0xbfbfece0
> ---------------------------------------------------------------------------
>
> If ++(*ptr) is supposed to increment the value *ptr, then why is there a
> change in memory address (0xbfbfece5) ?
Because after the first *ptr++; you actually have ptr == &ptr.
Miod
