On Tue, 17 Sep 2013, Raimo Niskanen wrote: > Suppose you are limited to length 1 strings of [a-z], then you have > 29 possible strings. > > Still. If you select one of those strings and calculates its SHA-1 > hash value. When you try any of the other 28 strings (or any other > string of any lenght) and calculates this other strings SHA-1 hash > value, the probability that it has the same hash value is 2 ^ (-160).
It seems likely that someone has calculated those hashes of 1 byte strings and determined that they have different hashes. If so, then the probability of having the same hash value would be zero, not 2^(-160). Eric
