Hi, On 20 July 2015 at 17:40, Emil Velikov <emil.l.veli...@gmail.com> wrote: > On 18 July 2015 at 23:13, Jonathan Gray <j...@jsg.id.au> wrote: >> $(RM) is set to 'rm -f' by GNU make, this is not true of other versions >> of make and RM is not one of the macros required by POSIX. >> > Slightly unfortunate but I think we can live with it. Would like to > see if Matt/other have objections against this, but as-is
I'd suggest using "RM ?= rm -f", but obviously that doesn't work on non-GNU make either ... Cheers, Daniel _______________________________________________ mesa-dev mailing list mesa-dev@lists.freedesktop.org http://lists.freedesktop.org/mailman/listinfo/mesa-dev
