Reviewed-by: Bruce Cherniak <bruce.chern...@intel.com>
> On Nov 12, 2016, at 5:00 PM, Ilia Mirkin <imir...@alum.mit.edu> wrote:
>
> In a BGR10X2 or BGR5X1 situation, there's no need to try to quantize the
> X channel - the default will have the proper quantization required.
>
> Signed-off-by: Ilia Mirkin <imir...@alum.mit.edu>
> ---
> src/gallium/drivers/swr/rasterizer/jitter/blend_jit.cpp | 2 +-
> 1 file changed, 1 insertion(+), 1 deletion(-)
>
> diff --git a/src/gallium/drivers/swr/rasterizer/jitter/blend_jit.cpp
> b/src/gallium/drivers/swr/rasterizer/jitter/blend_jit.cpp
> index 46ea495..d9c72a9 100644
> --- a/src/gallium/drivers/swr/rasterizer/jitter/blend_jit.cpp
> +++ b/src/gallium/drivers/swr/rasterizer/jitter/blend_jit.cpp
> @@ -220,7 +220,7 @@ struct BlendJit : public Builder
> const SWR_FORMAT_INFO& info = GetFormatInfo(format);
> for (uint32_t c = 0; c < info.numComps; ++c)
> {
> - if (info.bpc[c] <= QUANTIZE_THRESHOLD)
> + if (info.bpc[c] <= QUANTIZE_THRESHOLD && info.type[c] !=
> SWR_TYPE_UNUSED)
> {
> uint32_t swizComp = info.swizzle[c];
> float factor = (float)((1 << info.bpc[c]) - 1);
> --
> 2.7.3
>
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