On Fri, May 6, 2011 at 11:01 AM, Matt Turner <matts...@gmail.com> wrote:
> 1/ln(2) is equivalent to log2(e), so define it as such.
>
> log2(e) = ln(e)/ln(2) = 1/ln(2)
>
> Worst of all, the definitions for M_LOG2E and ONE_DIV_LN2
> (right beside each other!) weren't the same.
>
> Reviewed-by: Alex Deucher <alexdeuc...@gmail.com>
> Signed-off-by: Matt Turner <matts...@gmail.com>

I've applied this and the M_PI change.  Thanks.

-Brian
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