July, Erik Burggraaf User support consultant, Now posting occasionally on twitter at eburggraaf, 1-888-255-5194 http://www.erik-burggraaf.com
On 2011-06-06, at 5:17 PM, Ray Foret Jr wrote: > Any idea when Lion is coming out? > > > Sincerely, > The Constantly Barefooted Ray!!! > > Now a very proud and happy Mac user!!! > > Skype name: > barefootedray > > Facebook: > facebook.com/ray.foretjr.1 > > > > On Jun 6, 2011, at 4:13 PM, Christopher Wright wrote: > >> Hi all, >> One of the new features in Lion is the ability to sort email messages by >> conversation. Would this replace Mark's procedure for viewing messages by >> thread? >> >> Thanks. >> >> >> >> >> Christopher Wright - music composer, arranger, audio producer and >> performer >> Phone: 914-664-5014 >> email: chri...@bestweb.net >> web site: www.wright-media.com >> facebook: sign into your account and use the email address provided above >> Linked In: write to me for an invitation >> >> -- >> You received this message because you are subscribed to the Google Groups >> "MacVisionaries" group. >> To post to this group, send email to macvisionaries@googlegroups.com. >> To unsubscribe from this group, send email >> tomacvisionaries+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/macvisionaries?hl=en. > > > -- > You received this message because you are subscribed to the Google Groups > "MacVisionaries" group. > To post to this group, send email to macvisionaries@googlegroups.com. > To unsubscribe from this group, send email to > macvisionaries+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/macvisionaries?hl=en. -- You received this message because you are subscribed to the Google Groups "MacVisionaries" group. To post to this group, send email to macvisionaries@googlegroups.com. To unsubscribe from this group, send email to macvisionaries+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/macvisionaries?hl=en.
