Georg Baum wrote: >> for arg in $@ > > This needs to be: > > for arg in "@"
That's "$@" ? > as I learned recently from André. Otherwise it would print the same > wrong result even if the input was correct. Explanation please. -- Angus
Georg Baum wrote: >> for arg in $@ > > This needs to be: > > for arg in "@"
That's "$@" ? > as I learned recently from André. Otherwise it would print the same > wrong result even if the input was correct. Explanation please. -- Angus