Andre Poenitz wrote:
> On Thu, Mar 06, 2003 at 02:17:48PM +0000, Angus Leeming wrote:
>> Do things become clearer?
>
> Not sure.
>
> But
>
> ViewCitation(Dialog & parent) : ViewBase(parent) {}
> virtual void printcontroller() {
> std::cout << "ViewCitation's controller is "
> << getController<ControlCitation>().whoami()
>
> can _never_ work as I think you want as the ControlCitation type is
> static, so there is a static tie between ViewCitation and
> ControlCitation.
I'm interested only in static ties. I was just looking for a
shorthand notation... At the moment I have a templatised class from
which all the different individual views derive:
template<typename Controller>
class FormController : public FormDialogBase {
FormController(Dialog & parent) : FormDialogBase(paremt) {}
Controller & controller() { return (Controller &)controller_; }
};
That's all it does. It's just a shorthand. Thereafter
class FormCitation: public FormController<ControlCitation> {
...
}
so controller() to FormCitation means ControlCitation.
and to FormTabular it means Controltabular.
I wondered if I could get rid of this intermediate class and yet
still retain a shorthand notation. It appears not, but no matter. It
was just idle curiosity, that's all. Sorry it's exercised so much of
your attention.
> Every such construct _statically_ ties ControlCitation and
> ViewCitation...
>
> Ok...... Is the situation like that:
>
> We have a set of Controlers and a set of View.
> A dialog has one Controler and one View.
> In theory any Control can be couple with any View
> In practice, only a few combinations are useful.
> These combinations are static, i.e. established at compile
> time(?)
YES!
// Lazy instatiation. Only build the thing when a particular
// dialog is requested.
Dialog * Dialogs::build(string const & name) {
if (!isValid(name))
return 0;
Dialog * dialog = new Dialog;
if (name == "citation") {
dialog.setController(new ControlCitation(*dialog));
dialog.setView(new FormView(*dialog));
dialog.setButtonController(new NoRepeatedApplyBC);
} else if (name == "tabular") {
...
}
return dialog;
}
--
Angus
