Angus Leeming wrote:
>
> How do I best deal with BibTeX entries such as
> Stamenovi\'{c}
> or
> L\"{o}hner
>
> so that I can have pretty names in the citation dialog?
\'c and \"o are also possible.
> So, my question becomes:
> Is this the best way to do this and, if so, what goes in someFunc()?
i tried it with a translate vector:
( \'{c} , ç , \"{o} , ö , ... )
the i-th character is the original one and the i+1 the
translated. i is 0,1,2,3...
attached is a small sample for java, because i have no idea
of c++ ...
java bibtex "Vo\{ss} und S\\\"ohne" gives the output
Vo\{ss} und S\"ohne is converted to Voß und Söhne
Herbert
--
http://www.educat.hu-berlin.de/~voss/lyx/
public class bibtex {
String[] charTranslate = {
"\"a","ä", // orig chars without backslash
"\"A","Ä",
"\"o","ö",
"\"{o}","ö",
"\"O","Ö", // i is orig and i+1 is translate
"\"{O}","Ö",
"\"u","ü",
"\"U","ü",
"ss","ß",
"{ss}","ß",
};
char Slash = '\\';
public bibtex (String name) {
System.out.println( name+" is converted to "+translate(name));
}
public String translate (String name) {
int l=0, index;
int i = name.indexOf(Slash); // first slash
if (i<0) return name; // no special characters
String name2 = name.substring(0,i); // all until slash
name = name.substring(i); // the rest
do {
index=0;
while ((name.indexOf(charTranslate[index])!=1) && (index <
charTranslate.length-2))
index+=2;
if (index < charTranslate.length-1) { // chars found???
l = charTranslate[index].length(); // length of special chars
name2 = name2+charTranslate[++index]; // the translated chars
name = name.substring(l+1); // delete special characters
}
else { // no translate mode
name2 = name2+"\\"; // add backslash while unknown chars
name = name.substring(1); // delete backslash
}
i = name.indexOf(Slash); // next backslash?
if (i>0) {
name2 = name2+name.substring(0,i);
name = name.substring(i); // delete first characters
}
else return name2+name;
} while (true);
}
public static void main (String [] args) {
bibtex dummy = new bibtex(args[0]);
}
}
