On Fri, Sep 08, 2006 at 12:58:09PM +0200, Jean-Marc Lasgouttes wrote: > >>>>> "Enrico" == Enrico Forestieri <[EMAIL PROTECTED]> writes: > > >> Is you problem fixed now? > > Enrico> No, I have to use the attached patch. > > This is very strange, since the whole Makefile targets read: > > libgnuintl.h: $(srcdir)/libgnuintl.h.in > sed -e 's,@''HAVE_POSIX_PRINTF''@,@HAVE_POSIX_PRINTF@,g' \ > -e 's,@''HAVE_ASPRINTF''@,@HAVE_ASPRINTF@,g' \ > -e 's,@''HAVE_SNPRINTF''@,@HAVE_SNPRINTF@,g' \ > -e 's,@''HAVE_WPRINTF''@,@HAVE_WPRINTF@,g' \ > < $(srcdir)/libgnuintl.h.in > libgnuintl.h > > libintl.h: libgnuintl.h > cp libgnuintl.h libintl.h > > Are you sure that the fact that you have a $(srcdir)/libgnuintl.h > (which you should not have) does not prevent the creation of the > correct libgnuintl.h?
I am not sure what you mean. I am not changing any target, simply the rule to generate libintl.h: libintl.h: libgnuintl.h - cp libgnuintl.h libintl.h + cp $(srcdir)/libgnuintl.h libintl.h I don't see how this can fail... It seems that when libgnuintl.h is generated the current dir is $(srcdir), whereas when libintl.h is to be generated it is the build directory. -- Enrico
