Hi,
Fine,fork() always create new process, but here both the processes are
different stacks.
If I use foek(), it will run the same instance of ABC_stack ,rather XYZ_stack.
Shall we call the clone() with out CLONE_NEW* flags, so that it will run in
the same name space.
See the below scenario, multiple namespaces each namespace has to run two
different processes.
Main
{
Ns1=Clone(CLONE_NEWNS) ----> process1 (ABC_Stack)
|
. ---------->Process2 (XYZ_stack)
.
Ns2=Clone(CLONE_NEWNS) ----> process1 (ABC_Stack)
|
. ---------->Process2 (XYZ_stack)
.
.
.ns100clone(CLONE_NEWNS)
}
Thanks
Mahesh
-----Original Message-----
From: Rob Landley [mailto:[email protected]]
Sent: Wednesday, February 16, 2011 7:10 PM
To: [email protected]; Maheswara Reddy C - ERS, HCL Tech
Subject: Re: [lxc-devel] Two process on a same namespcae with clone()
On 02/16/2011 01:25 AM, Maheswara Reddy C - ERS, HCL Tech wrote:
> Hi,
>
> Could someone help me out,
>
> I want to run the two process on same name space, shall it possible
> using the clone()
You call clone with the CLONE_NEW* flags to create a new namespace. And
then you just fork() normally (without those flags) to create additional
processes in that same namespace.
It's a bit like chroot: you do something extra to get in it, and then
children inherit that environment by default.
Rob
P.S. Fix your hilarious legalese .sig.
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