Hi Aijun,
Yes – it seems ASBR-2 should be removed from the diagram.
Thanks,
Acee

From: Lsr <[email protected]> on behalf of Aijun Wang 
<[email protected]>
Date: Wednesday, March 11, 2020 at 6:48 AM
To: 'Sergey SHpenkov' <[email protected]>, "[email protected]" 
<[email protected]>
Subject: [Lsr] 答复: Question about OSPF (transit area routing loop)

Hi, Sergey:

If so, ABR-3 should also receive this SumLSA-4 for the ASBR(with cost 300), and 
then prefer the path via ABR-2 to reach ASBR(with cost 20).
Then there will be no loop then?

Or, how many SumLAS-4 will be advertised by ABR-1? If it selects and advertises 
only one (3 or 300), then the loop will not be emerged.
Currently, it seems it advertises this SumLAS-4 with the cost 300 to RT_1 and 
with the cost 3 to ABR-3?


Best Regards.

Aijun Wang
China Telecom

发件人: [email protected] [mailto:[email protected]] 代表 Sergey SHpenkov
发送时间: 2020年2月26日 15:20
收件人: [email protected]
主题: Re: [Lsr] Question about OSPF (transit area routing loop)

Acee,

Because ABR_1 creates SumLSA-4 for the ASBR not from the backbone area. The 
cost of SumLSA-4 for ASBR is 300.

Thanks,
Sergey

вт, 25 февр. 2020 г. в 22:44, Acee Lindem (acee) 
<[email protected]<mailto:[email protected]>>:
Hi Sergey,
I don’t see why RT_1 wouldn’t go through ABR_1 to get to the ASBR.
Thanks,
Acee

From: Lsr <[email protected]<mailto:[email protected]>> on behalf of 
Sergey SHpenkov 
<[email protected]<mailto:[email protected]>>
Date: Tuesday, February 25, 2020 at 2:38 PM
To: "[email protected]<mailto:[email protected]>" <[email protected]<mailto:[email protected]>>
Subject: [Lsr] Question about OSPF (transit area routing loop)

Hi,
In section 16.3 of the OSPF RFC 2328 standard, it is stated that all ABR routers
connected to a transit area are required to check the sumLSA contained within
this area in order to possibly improve the intra-area and inter-area backbone 
routes
for themselves.

See the picture:
[cid:[email protected]]
The RT_1 and ABR_3 routers will use different paths to the ASBR router:

ABR_3 -> RT_1 -> ABR_1 -> ASBR = cost 3
RT_1 -> ABR_3 -> ABR_2 -> ASBR = cost 21

route loop between RT_1 and ABR_3

Please explain this situation

Thanks,
Sergey

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