| Issue |
123052
|
| Summary |
Call to consteval method from constexpr constructor makes constructor consteval.
|
| Labels |
new issue
|
| Assignees |
|
| Reporter |
IViktorov
|
```C++
#include <cstdint>
#include <print>
template <class T, std::size_t kSize>
struct Test {
constexpr Test(const Test& t) noexcept: m_data{t.data()}, m_size{t.size()} {}
constexpr Test(T (&data)[kSize]) noexcept: m_data{data}, m_size{kSize} {}
constexpr T* data() const noexcept { return m_data; }
#ifdef NOCONSTEVAL
constexpr static std::size_t size() noexcept { return kSize; }
#else
consteval static std::size_t size() noexcept { return kSize; }
#endif
private:
T* m_data;
std::size_t m_size;
};
int main() {
int arr[] = {1, 2, 3, 4, 5, 6};
Test t1{arr};
Test t{t1};
std::println("arr[0] = {}, arr size = {}.", *t.data(), t.size());
}
```
With `consteval size()` method `Test` copy constructor becomes immediate function, but it should not.
Without consteval with `constexpr size()` everything goes as expected.
GCC doesn't have that problem with consteval methods, called in contructors.
https://godbolt.org/z/P157TafW8
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