Try target.AttachToProcessWithID() instead of target.LaunchSimple(). LaunchSimple tells lldb to run, creating a new process, instead of attaching to an existing one. See the SBTarget Python documentation here: https://lldb.llvm.org/python_reference/lldb.SBTarget-class.html .
You should also be able to attach using the lldb command line, then go into the scripting interface and get the debugger object with lldb.debugger . Or attach using debugger.HandleCommand() to run an lldb command from the scripting interface. Ted From: lldb-dev <lldb-dev-boun...@lists.llvm.org> On Behalf Of Pi Pony via lldb-dev Sent: Wednesday, November 3, 2021 10:20 AM To: lldb-dev@lists.llvm.org Subject: [lldb-dev] how to attach to process with python scripting on lldb? WARNING: This email originated from outside of Qualcomm. Please be wary of any links or attachments, and do not enable macros. Hello, I have been trying for some days to resolve a symbol of address using lldb python api but I haven't found how to do that. So I think that I need to attach to the PID using python but it's not working, I tried: target = lldb.debugger.FindTargetWithProcessID(71321) process = target.LaunchSimple(None, None, os.getcwd()) process.GetState() --> Returns 0 ... Why? So I could use the ResolveSymbolAddress function because if I attach it outside of scripting then I do not own the self – debugger object. I appreciate your help.
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