On Wed, Oct 21, 2015 at 12:29:23PM -0700, Paul E. McKenney wrote: > On Wed, Oct 21, 2015 at 10:24:52AM +0200, Peter Zijlstra wrote: > > On Tue, Oct 20, 2015 at 04:34:51PM -0700, Paul E. McKenney wrote: > > > There is also the question of whether the barrier forces ordering > > > of unrelated stores, everything initially zero and all accesses > > > READ_ONCE() or WRITE_ONCE(): > > > > > > P0 P1 P2 P3 > > > X = 1; Y = 1; r1 = X; r3 = Y; > > > some_barrier(); some_barrier(); > > > r2 = Y; r4 = X; > > > > > > P2's and P3's ordering could be globally visible without requiring > > > P0's and P1's independent stores to be ordered, for example, if you > > > used smp_rmb() for some_barrier(). In contrast, if we used smp_mb() > > > for barrier, everyone would agree on the order of P0's and P0's stores. > > > > Oh!? > > Behold sequential consistency, worshipped fervently by a surprisingly > large number of people! Something about legacy proof methods, as near > as I can tell. ;-)
But how can smp_mb() guarantee anything about P[01]? There is but the single store, which can race against P[23] arbitrarily. There is nothing to order. Maybe I'm confused again.. _______________________________________________ Linuxppc-dev mailing list Linuxppc-dev@lists.ozlabs.org https://lists.ozlabs.org/listinfo/linuxppc-dev
