One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example:
struct foo { int stuff; void *entry[]; }; instance = kmalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kmalloc(struct_size(instance, entry, count), GFP_KERNEL); This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gust...@embeddedor.com> --- arch/powerpc/platforms/cell/spufs/file.c | 5 ++--- 1 file changed, 2 insertions(+), 3 deletions(-) diff --git a/arch/powerpc/platforms/cell/spufs/file.c b/arch/powerpc/platforms/cell/spufs/file.c index ae8123edddc6..48c2477e7e2a 100644 --- a/arch/powerpc/platforms/cell/spufs/file.c +++ b/arch/powerpc/platforms/cell/spufs/file.c @@ -2338,9 +2338,8 @@ static int spufs_switch_log_open(struct inode *inode, struct file *file) goto out; } - ctx->switch_log = kmalloc(sizeof(struct switch_log) + - SWITCH_LOG_BUFSIZE * sizeof(struct switch_log_entry), - GFP_KERNEL); + ctx->switch_log = kmalloc(struct_size(ctx->switch_log, log, + SWITCH_LOG_BUFSIZE), GFP_KERNEL); if (!ctx->switch_log) { rc = -ENOMEM; -- 2.20.1