On Wed, 2016-02-03 at 11:24 -0500, Alan Stern wrote:
> On Wed, 3 Feb 2016, Oliver Neukum wrote:
> 
> > Some devices I got show an inability to operate right after
> > power on if they are already connected. They are beyond recovery
> > if the descriptors are requested multiple times. So in case of
> > a timeout we rather bail early and reset again.
> > 
> > This patch is a rework of a patch that fell through the cracks.
> > http://www.spinics.net/lists/linux-usb/msg103263.html
> > 
> > Signed-off-by: Oliver Neukum <oneu...@suse.com>
> > CC: sta...@vger.kernel.org
> > ---
> >  drivers/usb/core/hub.c | 7 ++++++-
> >  1 file changed, 6 insertions(+), 1 deletion(-)
> > 
> > diff --git a/drivers/usb/core/hub.c b/drivers/usb/core/hub.c
> > index f912fe6..2124c4e 100644
> > --- a/drivers/usb/core/hub.c
> > +++ b/drivers/usb/core/hub.c
> > @@ -4496,7 +4496,12 @@ hub_port_init(struct usb_hub *hub, struct usb_device 
> > *udev, int port1,
> >                                             r = -EPROTO;
> >                                     break;
> >                             }
> > -                           if (r == 0)
> > +                           /*
> > +                            * Some devices time out if they are powered on
> > +                            * when already connected. They need a second
> > +                            * reset.
> > +                            */
> > +                           if (r == 0  || r == -ETIMEDOUT)
> >                                     break;
> >                     }
> >                     udev->descriptor.bMaxPacketSize0 =
> > 
> 
> Hmmm.  Your device fails completely if there are multiple attempts 
> without a reset in between, right?
> 
> What about devices which always time out the first control request
> after a reset?  I can't be certain any such devices exist, but it
> wouldn't be surprising given the range of hardware bugs in USB devices.
> 
> Would it be safer to do this instead?
> 
>                               if (r == 0 || (r == -ETIMEDOUT &&
>                                               j = 0))
>                                       break;
Indeed. Greg, I'll make an improved patch.

        Regards
                Oliver




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