On Tue, 13 May 2014, Todd E Brandt wrote:
> This patch creates a separate instance of the usb_address0 mutex for each host
> controller, and attaches it to the host controller device struct. This allows
> devices on separate hosts to be enumerated in parallel; saving time.
>
> In the current code, there is a single, global instance of the usb_address0
> mutex which is used for all devices on any host. This isn't completely
> necessary, as this mutex is only needed to prevent address0 collisions for
> devices on the *same* host (usb 2.0 spec, sec 4.6.1). This superfluous
> coverage
> can cause additional delay in system resume on systems with multiple hosts
> (up to several seconds depending on what devices are attached).
>
> For instance, if I have a USB WLAN and a KVM switch attached to two ports,
> there's a chance that they could be initialized at the same time (e.g. on
> system resume). They would both be in the Default state and would be
> responding to requests from the default address (address 00H). If they were
> on the same host, there'd be no way of differentiating the two devices and
> thus
> the mutex is needed. But on separate hosts there's no chance of collision.
>
> Signed-off-by: Todd Brandt <todd.e.bra...@linux.intel.com>
Does this really save any meaningful amount of time? Have you measured
it?
> --- a/drivers/usb/core/hcd.c
> +++ b/drivers/usb/core/hcd.c
> @@ -2452,9 +2452,18 @@ struct usb_hcd *usb_create_shared_hcd(const struct
> hc_driver *driver,
> return NULL;
> }
> mutex_init(hcd->bandwidth_mutex);
> + hcd->usb_address0_mutex =
> + kmalloc(sizeof(*hcd->usb_address0_mutex), GFP_KERNEL);
> + if (!hcd->usb_address0_mutex) {
> + kfree(hcd);
> + dev_dbg(dev, "hcd usb_address0 mutex alloc failed\n");
> + return NULL;
> + }
> + mutex_init(hcd->usb_address0_mutex);
Why do you allocate the mutex dynamically? Why not simply use a static
mutex embedded in the usb_hcd structure?
Alan Stern
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