On 04/27, Oleg Nesterov wrote: > > On 04/27, Eric W. Biederman wrote: > > > > Oleg Nesterov <o...@redhat.com> writes: > > > > > On 04/26, Eric W. Biederman wrote: > > >> > > >> @@ -253,7 +252,7 @@ static int ptrace_check_attach(struct task_struct > > >> *child, bool ignore_state) > > >> */ > > >> if (lock_task_sighand(child, &flags)) { > > >> if (child->ptrace && child->parent == current) { > > >> - WARN_ON(READ_ONCE(child->__state) == > > >> __TASK_TRACED); > > >> + WARN_ON(child->jobctl & JOBCTL_DELAY_WAKEKILL); > > > > > > This WARN_ON() doesn't look right. > > > > > > It is possible that this child was traced by another task and > > > PTRACE_DETACH'ed, > > > but it didn't clear DELAY_WAKEKILL. > > > > That would be a bug. That would mean that PTRACE_DETACHED process can > > not be SIGKILL'd. > > Why? The tracee will take siglock, clear JOBCTL_DELAY_WAKEKILL and notice > SIGKILL after that.
Not to mention that the tracee is TASK_RUNNING after PTRACE_DETACH wakes it up, so the pending JOBCTL_DELAY_WAKEKILL simply has no effect. Oleg. > > > If the new debugger attaches and calls ptrace() before the child takes > > > siglock > > > ptrace_freeze_traced() will fail, but we can hit this WARN_ON(). > > > > Eric > > _______________________________________________ linux-um mailing list linux-um@lists.infradead.org http://lists.infradead.org/mailman/listinfo/linux-um