While commit 37868fe113 ("x86/ldt: Make modify_ldt synchronous") added
a nice comment explaining that Xen needs page-aligned whole page chunks
for guest descriptor tables, it then nevertheless used kzalloc() on the
small size path. As I'm unaware of guarantees for kmalloc(PAGE_SIZE, )
to return page-aligned memory blocks, I believe this needs to be
switched back to __get_free_page() (or better get_zeroed_page()).
Signed-off-by: Jan Beulich <jbeul...@suse.com>
Cc: Andy Lutomirski <l...@kernel.org>
Cc: Boris Ostrovsky <boris.ostrov...@oracle.com>
Cc: David Vrabel <david.vra...@citrix.com>
Cc: Konrad Rzeszutek Wilk <konrad.w...@oracle.com>
---
v3: Use get_zeroed_page() and free_page() respectively.
---
arch/x86/kernel/ldt.c | 4 ++--
1 file changed, 2 insertions(+), 2 deletions(-)
--- 4.2/arch/x86/kernel/ldt.c
+++ 4.2-x86-LDT-alloc/arch/x86/kernel/ldt.c
@@ -58,7 +58,7 @@ static struct ldt_struct *alloc_ldt_stru
if (alloc_size > PAGE_SIZE)
new_ldt->entries = vzalloc(alloc_size);
else
- new_ldt->entries = kzalloc(PAGE_SIZE, GFP_KERNEL);
+ new_ldt->entries = (void *)get_zeroed_page(GFP_KERNEL);
if (!new_ldt->entries) {
kfree(new_ldt);
@@ -95,7 +95,7 @@ static void free_ldt_struct(struct ldt_s
if (ldt->size * LDT_ENTRY_SIZE > PAGE_SIZE)
vfree(ldt->entries);
else
- kfree(ldt->entries);
+ free_page((unsigned long)ldt->entries);
kfree(ldt);
}
--
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