gcc doesn't merge or overlap const char[] objects with identical
contents (probably language lawyers would also insist that these
things have different addresses), but there's no reason to have the
string "0123456789ABCDEF" occur in multiple places. hex_asc_upper is
declared in kernel.h and defined in lib/hexdump.c, which is
unconditionally compiled in.
Signed-off-by: Rasmus Villemoes <li...@rasmusvillemoes.dk>
---
lib/vsprintf.c | 7 ++-----
1 file changed, 2 insertions(+), 5 deletions(-)
diff --git a/lib/vsprintf.c b/lib/vsprintf.c
index 98f1ce907d3d..7a299d43987a 100644
--- a/lib/vsprintf.c
+++ b/lib/vsprintf.c
@@ -383,9 +383,6 @@ static noinline_for_stack
char *number(char *buf, char *end, unsigned long long num,
struct printf_spec spec)
{
- /* we are called with base 8, 10 or 16, only, thus don't need "G..." */
- static const char digits[16] = "0123456789ABCDEF"; /*
"GHIJKLMNOPQRSTUVWXYZ"; */
-
char tmp[3 * sizeof(num)];
char sign;
char locase;
@@ -422,7 +419,7 @@ char *number(char *buf, char *end, unsigned long long num,
/* generate full string in tmp[], in reverse order */
i = 0;
if (num < spec.base)
- tmp[i++] = digits[num] | locase;
+ tmp[i++] = hex_asc_upper[num] | locase;
else if (spec.base != 10) { /* 8 or 16 */
int mask = spec.base - 1;
int shift = 3;
@@ -430,7 +427,7 @@ char *number(char *buf, char *end, unsigned long long num,
if (spec.base == 16)
shift = 4;
do {
- tmp[i++] = (digits[((unsigned char)num) & mask] |
locase);
+ tmp[i++] = (hex_asc_upper[((unsigned char)num) & mask]
| locase);
num >>= shift;
} while (num);
} else { /* base 10 */
--
2.1.3
--
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