On Fri 2014-11-07 13:56:09, Steven Rostedt wrote:
> On Thu, 6 Nov 2014 19:41:55 +0100
> Petr Mladek <[email protected]> wrote:
>  
> > >  /* "in progress" flag of arch_trigger_all_cpu_backtrace */
> > >  static unsigned long backtrace_flag;
> > >  
> > > +static void print_seq_line(struct nmi_seq_buf *s, int last, int pos)
> > 
> > I would rename the arguments:
> > 
> >     "last -> first"
> >     "pos -> last"
> > 
> > or maybe better would be to pass first positon and len.
> 
> I switched it to "start" and "end" to not be confused by the last_i
> that is being passed in.

I like it.

> > 
> > > +{
> > > + const char *buf = s->buffer + last;
> > > +
> > > + printk("%.*s", (pos - last) + 1, buf);
> > > +}
> > 
> 
> 
> 
> > >  
> > > + /*
> > > +  * Now that all the NMIs have triggered, we can dump out their
> > > +  * back traces safely to the console.
> > > +  */
> > > + for_each_cpu(cpu, printtrace_mask) {
> > > +         int last_i = 0;
> > > +
> > > +         s = &per_cpu(nmi_print_seq, cpu);
> > > +         len = s->seq.len;
> > 
> > If there is an seq_buf overflow, the len might be size + 1, so we need to 
> > do:
> > 
> >             len = min(s->seq.len, s->size);
> > 
> > Well, we should create a function for this in seq_buf.h.
> > Alternatively, we might reconsider the overflow state,
> > use len == size and extra "overflow" flag in the seq_buf struct.
> > 
> > 
> > > +         if (!len)
> > > +                 continue;
> > > +
> > > +         /* Print line by line. */
> > > +         for (i = 0; i < len; i++) {
> > > +                 if (s->buffer[i] == '\n') {
> > > +                         print_seq_line(s, last_i, i);
> > > +                         last_i = i + 1;
> > > +                 }
> > > +         }
> > >
> > > +         if (last_i < i - 1) {
> > 
> > IMHO, this should be:
> > 
> >             if (last_i < i)
> > 
> > because last_i = i + 1. Otherwise, we would ignore state when there is
> > one character after a new line. For example, imagine the following:
> > 
> >     buffer = "a\nb";
> >     len = 3;
> > 
> > it will end with:
> > 
> >     last_i = 2;
> >     i = 3;
> > 
> > and we still need to print the "b".
> 
> Well, we really don't *need* to ;-)
> 
> But for correctness sake, I agree, it should be last_i < i.

I agree that one more character does not make much difference but
it might save someones day :-)

> > 
> > > +                 print_seq_line(s, last_i, i);
> > 
> > If I get it correctly, (i == len) here and "printk_seq_line"
> > print_seq_line() prints the characters including "pos" value.
> > So, we should call:
> > 
> >                     print_seq_line(s, last_i, i - 1)
> 
> Right that was wrong. Actually, I think the best answer would be:
> 
>       print_seq_line(s, last_i, len - 1);

Yup

> This removes the variable 'i'. Probably should add a comment here too
> that reminds the reviewer that print_seq_line() prints up to and
> including the last index.

Yes, the comment is worth having.

> Note, my current code also has:
> 
>       len = seq_buf_used(&s->seq);
> 
> where we don't need to worry about the semantics of seq_buf internals.

Perfect

Thanks a lot for working on it. Please, resend this patch once you are
happy with it.

Best Regards,
Petr
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