Hi,
I didn't go deeper in atmel_nand.c code to see other accesses but old
copy use writel_relaxed which is a macro to __raw_writel((__force u32)
cpu_to_le32(v),c)
__iowrite32_copy use directly __raw_writel(*src++, dst++)
So we skip cpu_to_le32. Is it ok for all system using atmel_nand ?
Best regards,
Herve Codina
Le 21/10/2014 12:03, Josh Wu a écrit :
> Hi, Vinod
>
> On 10/21/2014 12:06 AM, Vinod Koul wrote:
>> The driver was also using own method to do 32bit copy, turns out
>> we have a kernel API so use that instead
>>
>> Signed-off-by: Vinod Koul <vinod.k...@intel.com>
>
> Thanks for the patch.
> Acked-by: Josh Wu <josh...@atmel.com>
>
> BTW, is there any similar kernel API that is for the read from io?
>
> Best Regards,
> Josh Wu
>
>> ---
>> drivers/mtd/nand/atmel_nand.c | 10 +++-------
>> 1 files changed, 3 insertions(+), 7 deletions(-)
>>
>> diff --git a/drivers/mtd/nand/atmel_nand.c b/drivers/mtd/nand/atmel_nand.c
>> index e321c56..b03e80d 100644
>> --- a/drivers/mtd/nand/atmel_nand.c
>> +++ b/drivers/mtd/nand/atmel_nand.c
>> @@ -265,14 +265,10 @@ static void memcpy32_fromio(void *trg, const void
>> __iomem *src, size_t size)
>> *t++ = readl_relaxed(s++);
>> }
>>
>> -static void memcpy32_toio(void __iomem *trg, const void *src, int size)
>> +static inline void memcpy32_toio(void __iomem *trg, const void *src, int
>> size)
>> {
>> - int i;
>> - u32 __iomem *t = trg;
>> - const u32 *s = src;
>> -
>> - for (i = 0; i < (size >> 2); i++)
>> - writel_relaxed(*s++, t++);
>> + /* __iowrite32_copy use 32bit size values so divide by 4 */
>> + __iowrite32_copy(trg, src, size/4);
>> }
>>
>> /*
>
--
To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to majord...@vger.kernel.org
More majordomo info at http://vger.kernel.org/majordomo-info.html
Please read the FAQ at http://www.tux.org/lkml/
