There is no need to mark the lower interrupts as reserved in order to
exclude them from dynamic allocation.
Provide arch_dynirq_lower_bound() to exclude the lower space.
Signed-off-by: Thomas Gleixner <t...@linutronix.de>
Cc: Martin Schwidefsky <schwidef...@de.ibm.com>
Cc: Heiko Carstens <heiko.carst...@de.ibm.com>
Cc: linux...@de.ibm.com
---
arch/s390/kernel/irq.c | 6 +++++-
1 file changed, 5 insertions(+), 1 deletion(-)
Index: tip/arch/s390/kernel/irq.c
===================================================================
--- tip.orig/arch/s390/kernel/irq.c
+++ tip/arch/s390/kernel/irq.c
@@ -92,7 +92,6 @@ static const struct irq_class irqclass_s
void __init init_IRQ(void)
{
- irq_reserve_irqs(0, THIN_INTERRUPT);
init_cio_interrupts();
init_airq_interrupts();
init_ext_interrupts();
@@ -151,6 +150,11 @@ out:
return 0;
}
+unsigned int arch_dynirq_lower_bound(unsigned int from)
+{
+ return from < THIN_INTERRUPT ? THIN_INTERRUPT : from;
+}
+
/*
* Switch to the asynchronous interrupt stack for softirq execution.
*/
--
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