From: Wang YanQing <udkni...@gmail.com>

The current "help" that comes out of the snapshot file when it is
not allocated looks like this:

 # * Snapshot is freed *
 #
 # Snapshot commands:
 # echo 0 > snapshot : Clears and frees snapshot buffer
 # echo 1 > snapshot : Allocates snapshot buffer, if not already allocated.
 #                      Takes a snapshot of the main buffer.
 # echo 2 > snapshot : Clears snapshot buffer (but does not allocate)
 #                      (Doesn't have to be '2' works with any number that
 #                       is not a '0' or '1')

Echo 2 says that it does not allocate the buffer, which is correct,
but to be more consistent with "echo 0" it should also state
that it does not free.

Link: http://lkml.kernel.org/r/20130914045916.GA4243@udknight

Signed-off-by: Wang YanQing <udkni...@gmail.com>
Signed-off-by: Steven Rostedt <rost...@goodmis.org>
---
 kernel/trace/trace.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/kernel/trace/trace.c b/kernel/trace/trace.c
index 7974ba2..d5f7c4d 100644
--- a/kernel/trace/trace.c
+++ b/kernel/trace/trace.c
@@ -2760,7 +2760,7 @@ static void show_snapshot_main_help(struct seq_file *m)
        seq_printf(m, "# echo 0 > snapshot : Clears and frees snapshot 
buffer\n");
        seq_printf(m, "# echo 1 > snapshot : Allocates snapshot buffer, if not 
already allocated.\n");
        seq_printf(m, "#                      Takes a snapshot of the main 
buffer.\n");
-       seq_printf(m, "# echo 2 > snapshot : Clears snapshot buffer (but does 
not allocate)\n");
+       seq_printf(m, "# echo 2 > snapshot : Clears snapshot buffer (but does 
not allocate or free)\n");
        seq_printf(m, "#                      (Doesn't have to be '2' works 
with any number that\n");
        seq_printf(m, "#                       is not a '0' or '1')\n");
 }
-- 
1.8.4.rc3


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