We are saving first scheduling domain for a cpu in build_sched_domains() by
iterating over the nested sd->child list. We don't actually need to do it this
way.

*per_cpu_ptr(d.sd, i) is guaranteed to be NULL in the beginning as we have
called __visit_domain_allocation_hell() which does a memset to zero for struct
s_data.

So, save pointer to first SD while running the iteration loop over tl's.

Signed-off-by: Viresh Kumar <viresh.ku...@linaro.org>
---
 kernel/sched/core.c | 7 ++-----
 1 file changed, 2 insertions(+), 5 deletions(-)

diff --git a/kernel/sched/core.c b/kernel/sched/core.c
index 58453b8..638f6cb 100644
--- a/kernel/sched/core.c
+++ b/kernel/sched/core.c
@@ -6533,16 +6533,13 @@ static int build_sched_domains(const struct cpumask 
*cpu_map,
                sd = NULL;
                for (tl = sched_domain_topology; tl->init; tl++) {
                        sd = build_sched_domain(tl, &d, cpu_map, attr, sd, i);
+                       if (!*per_cpu_ptr(d.sd, i))
+                               *per_cpu_ptr(d.sd, i) = sd;
                        if (tl->flags & SDTL_OVERLAP || 
sched_feat(FORCE_SD_OVERLAP))
                                sd->flags |= SD_OVERLAP;
                        if (cpumask_equal(cpu_map, sched_domain_span(sd)))
                                break;
                }
-
-               while (sd->child)
-                       sd = sd->child;
-
-               *per_cpu_ptr(d.sd, i) = sd;
        }
 
        /* Build the groups for the domains */
-- 
1.7.12.rc2.18.g61b472e

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