>>> @@ -749,7 +756,13 @@ static int posix_cpu_timer_set(struct k_itimer *timer,
>>> int flags,
>>> }
>>>
>>> if (new_expires.sched != 0 && !(flags & TIMER_ABSTIME)) {
>>> - cpu_time_add(timer->it_clock, &new_expires, val);
>>> + union cpu_time_count now;
>>> +
>>> + if (CPUCLOCK_PERTHREAD(timer->it_clock))
>>> + cpu_clock_sample(timer->it_clock, p, &now);
>>> + else
>>> + cpu_clock_sample_group(timer->it_clock, p, &now);
>>
>> This triggered a pattern match against earlier in this function; but they're
>> different now; timer vs clock. So nothing to merge...
>
> Not different, I think.
> Relative timeout need to calculate "now + timeout" by definition.
>
> But which time is "now"?
>
> Example, thread1 has 10ms sum_exec_runtime and 4ms delta and call
> timer_settime(4ms).
> Old code calculate an expire is 10+4=14. New one calculate 10+4+4=18.
>
> Which expire is correct? When using old one, timer will fire just after
> syscall. This
> is posix violation.
>
> In the other words,
>
> sighandler(){
> t1 = clock_gettime()
> }
>
> t0 = clock_gettime()
> timer_settime(timeout);
> ... wait to fire
>
> assert (t1 - t0 >= timeout)
>
> This pseudo code must be true. it is snippest what glibc rt/tst-cputimer1
> test and failed.
In the other hands, following two calculations need to timer time (aka time
without delta).
1) Initialization signal->cputimer for avoiding double delta count.
2) calculating old tiemr because timer firing logic (run_posix_cpu_timers)
don't care delta_exec.
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