Le Wed, 2 May 2001 13:55:34 +0200 
Ofer Fryman <[EMAIL PROTECTED]> à écrit :

> The definition of ioctl is "extern int __ioctl __P ((int __fd, unsigned long
> int __request, ...));" on Linux 2.0.x, and I believe it is also on any other
> Linux version.

yes but I use an network device specific ioctl call wich perform interface-specific
ioctl commands.
the prototype of the ioctl reception in the module is (as described in rubini book,
O reilly, linux device drivers):

int (*do_ioctl) (struct device *dev, struct ifreq *ifr, int cmd);

so can I pass over the limitations of the definition ?
I do ioctl that use private ioctl flags (e.g. SIOCDEVPRIVATE)

> So If you can pass what ever pointer or number you want instead of struct
> ifreq, If you use Linux under 2.2.x you will need to use copy_fromfs to get
> the buffer info, otherwise you can access it directly from the kernel mode
> with the restriction of interrupt handlers and bottom-halfs. 
> 
> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, May 02, 2001 10:08 AM
> To: liste noyau linux
> Subject: ioctl call for network device
> 
> 
> Hi,
> 
> I've succeed to do an ioctl call and recept it in my module
> 
> ioctl(file_descriptor, cmd, struct ifreq)
> 
> but I believe that I'm oblige to use the struct ifreq and I can't
> pass any other arguments because an user can't acces kernel space
> so the ioctl call recopy data in the kernel space (this is what I've
> understood, maybe I'm wrong ...).
> 
> My problem is that I need to pass some int arguments (the best way was an
> int* ) but the struct ifreq doesn't permit me it, so could I add other
> arguments as we can do in an normal ioctl call ?
> 
> I hope this is the wrong place for this question.
> 
> sebastien person
> -
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