On Wed, Jul 18, 2012 at 04:00:49PM -0400, Jim Rees wrote:
> You could use something like:
>
> char tbuf[sizeof (unsigned long) * 24 / 10 + 1 + 2]; /* + 2 for final
> "\n\0" */
>
> since there are roughly 10 bits for every 3 decimal digits.
>
> But I'm obviously confused, because I don't understand why tbuf needs to be
> any more than 10 + 2.
Unsigned long isn't necessarily 32 bits.
On 64-bit systems %lu can be up to 18446744073709551615
Dave
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