Dave Hansen <[EMAIL PROTECTED]> writes:

> On Fri, 2007-10-26 at 14:37 -0600, Eric W. Biederman wrote:
>> 
>> +static int pid_in_pid_ns(struct pid *pid, struct pid_namespace *ns)
>> +{
>> +       return pid && (ns->level <= pid->level) &&
>> +               pid->numbers[ns->level].ns == ns;
>> +}
>
> Could we blow this out a little bit?  (I think the blown-out version
> lends itself to being better commented, and easier to read.)  Also, can
> we think of any better name for this?  It seems a bit funky that:
>
>       pid_in_pid_ns(mypid, &init_pid_ns);
>
> would _ever_ return 0.

It can't.

> So, it isn't truly a test for belonging *in* a
> namespace, but having that namespace be the lowest level one. 

No.  It is precisely a test for being in a namespace.
We first check ns->level to make certain it doesn't fall out
of the array, and then we check to see if the namespace we
are looking for is at that level.

pid->numbers[0].ns == &init_pid_ns.

> I think
> Suka toyed with calling it an "active" or "primary" pid namespace.  That
> differentiated mere membership in a pid namespace from the one that
> actually molds that pid's view of the world.

What we want for the test is a test for membership.


> static int pid_in_pid_ns(struct pid *pid, struct pid_namespace *ns)
> {
>       if (!pid)
>               return 0;
>       if (ns->level > pid->level)
>               return 0;
>       if (pid->numbers[ns->level].ns != ns)
>               return 0;
>       return 1;
> }

I don't have a problem with that.  The rest of the checks for
this in kernel/pid.c are in the same form.

Eric

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