Axel Lin <axel....@ingics.com> 於 2019年6月27日 週四 上午7:58寫道： > > > > With your current code where LM36274_LDO_VSEL_MAX and n_voltages is 0x34, > > > the maximum voltage will become 400000 + 50000 * 0x34 = 6.6V which > > > does not match the datasheet. > > > > Not sure how you get 6.6v the LDO max is 6.5v. > > > > After 0x32->0x7f maps to 6.5v > > > > 000000 = 4 V > > 000001 = 4.05 V > > : > > 011110 = 5.5 V (Default) > > : > > 110010 = 6.5 V > > > > 110011 to 111111 map to 6.5 V <- Should never see 6.6v from LDO > > > > Page 7 of the Datasheet says range is 4v->6.5v > Hi Dan, > > The device indeed can only support up to 6.5V, the point is you are using > linear equation to calculate the voltage of each selecter. > In your current code: > #define LM36274_LDO_VSEL_MAX 0x34 (and it's .n_voltages) > So it supports selector 0 ... 0x33. > For selector 0x33 in the linear equation is > 4000000 + 50000 * 51 = 6550000 (i.e. 6.55V) > i.e. The device actually only support up to 6.5V but the driver > reports it support up to 6.55V > because regulator_list_voltage() will return 6.55V for selector 0x33. > (I have off-by-one in my previous reply because when .n_voltages is > 0x34, it supports up to 0x33)
Similar comment as I mentioned in another path. Did you check regulator_list_voltage() output for the boundary case with and without this patch?
