On 5/28/19 7:35 AM, Anshuman Khandual wrote:


On 05/23/2019 03:52 PM, Ard Biesheuvel wrote:
Now that the core code manages the executable permissions of code
regions of modules explicitly, it is no longer necessary to create

I guess the permission transition for various module sections happen
through module_enable_[ro|nx]() after allocating via module_alloc().


Indeed.

the module vmalloc regions with RWX permissions, and we can create
them with RW- permissions instead, which is preferred from a
security perspective.

Makes sense. Will this be followed in all architectures now ?


I am not sure if every architecture implements module_enable_[ro|nx](), but if they do, they should probably apply this change as well.


Signed-off-by: Ard Biesheuvel <ard.biesheu...@arm.com>
---
  arch/arm64/kernel/module.c | 4 ++--
  1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/arch/arm64/kernel/module.c b/arch/arm64/kernel/module.c
index 2e4e3915b4d0..88f0ed31d9aa 100644
--- a/arch/arm64/kernel/module.c
+++ b/arch/arm64/kernel/module.c
@@ -41,7 +41,7 @@ void *module_alloc(unsigned long size)
p = __vmalloc_node_range(size, MODULE_ALIGN, module_alloc_base,
                                module_alloc_base + MODULES_VSIZE,
-                               gfp_mask, PAGE_KERNEL_EXEC, 0,
+                               gfp_mask, PAGE_KERNEL, 0,
                                NUMA_NO_NODE, __builtin_return_address(0));
if (!p && IS_ENABLED(CONFIG_ARM64_MODULE_PLTS) &&
@@ -57,7 +57,7 @@ void *module_alloc(unsigned long size)
                 */
                p = __vmalloc_node_range(size, MODULE_ALIGN, module_alloc_base,
                                module_alloc_base + SZ_4G, GFP_KERNEL,
-                               PAGE_KERNEL_EXEC, 0, NUMA_NO_NODE,
+                               PAGE_KERNEL, 0, NUMA_NO_NODE,
                                __builtin_return_address(0));
if (p && (kasan_module_alloc(p, size) < 0)) {


Which just makes sure that PTE_PXN never gets dropped while creating
these mappings.


Not sure what you mean. Is there a question here?


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