On Monday 20 August 2007 19:56, Jan Hubicka wrote:
> > > > The problem is with the optimization flags: passing -Os causes the
> > > > compiler to be stupid and not inline any memset/memcpy functions.
> > >
> > > you get what you ask for.. if you don't want that then don't ask for
> > > it ;)
> >
> > Well, the compiler is really being dumb about -Os and in fact it's
> > giving bigger code, so I'm not really getting what I ask for.
> >
> > With my gcc at least (x86_64, gcc (GCC) 4.1.3 20070812 (prerelease)
> > (Ubuntu 4.1.2-15ubuntu2)) and Andi's example:
> >
> > #include <string.h>
> >
> > f(char x[6]) {
> > memset(x, 1, 6);
> > }
> >
> > compiling with -O2 gives
> >
> > 0000000000000000 <f>:
> > 0: c7 07 01 01 01 01 movl $0x1010101,(%rdi)
> > 6: 66 c7 47 04 01 01 movw $0x101,0x4(%rdi)
> > c: c3 retq
>
> GCC mainline (ie future GCC4.3.0) now give:
> 0000000000000000 <f>:
> 0: b0 01 mov $0x1,%al
> 2: b9 06 00 00 00 mov $0x6,%ecx
> 7: f3 aa rep stos %al,%es:(%rdi)
> 9: c3 retq
> That is smallest, definitly not fastest.
> GCC up to 4.3.0 won't be able to inline memset with non-0 operand...
No, it's not smallest. This one is smaller by 1 byte, maybe faster
(rep ... prefix is microcoded -> slower) and frees %ecx for other uses:
mov $0x01010101,%eax # 5 bytes
stosl # 1 byte
stosw # 2 bytes
retq
--
vda
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