One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example:
struct foo { int stuff; void *entry[]; }; instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL); This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gust...@embeddedor.com> --- drivers/misc/enclosure.c | 4 +--- 1 file changed, 1 insertion(+), 3 deletions(-) diff --git a/drivers/misc/enclosure.c b/drivers/misc/enclosure.c index 5a17bfeb80d3..74d4fda6c4a7 100644 --- a/drivers/misc/enclosure.c +++ b/drivers/misc/enclosure.c @@ -125,9 +125,7 @@ enclosure_register(struct device *dev, const char *name, int components, struct enclosure_component_callbacks *cb) { struct enclosure_device *edev = - kzalloc(sizeof(struct enclosure_device) + - sizeof(struct enclosure_component)*components, - GFP_KERNEL); + kzalloc(struct_size(edev, component, components), GFP_KERNEL); int err, i; BUG_ON(!cb); -- 2.20.1