On Thu, Aug 09, 2018 at 12:04:41PM +1000, NeilBrown wrote:
> In a future patch we will need to differentiate between conflicts that
> are "transitive" and those that aren't.
> A "transitive" conflict is defined as one where any lock that
> conflicts with the first (newly requested) lock would conflict with
> the existing lock.
> 
> So change posix_locks_conflict(), flock_locks_conflict() (both
> currently returning int) and leases_conflict() (currently returning
> bool) to return "enum conflict".
> Add locks_transitive_overlap() to make it possible to compute the
> correct conflict for posix locks.
> 
> The FL_NO_CONFLICT value is zero, so current code which only tests the
> truth value of these functions will still work the same way.
> 
> And convert some
>    return (foo);
> to
>    return foo;
> 
> Signed-off-by: NeilBrown <ne...@suse.com>
> ---
>  fs/locks.c |   64 
> ++++++++++++++++++++++++++++++++++++++++++++++--------------
>  1 file changed, 49 insertions(+), 15 deletions(-)
> 
> diff --git a/fs/locks.c b/fs/locks.c
> index b4812da2a374..d06658b2dc7a 100644
> --- a/fs/locks.c
> +++ b/fs/locks.c
> @@ -139,6 +139,16 @@
>  #define IS_OFDLCK(fl)        (fl->fl_flags & FL_OFDLCK)
>  #define IS_REMOTELCK(fl)     (fl->fl_pid <= 0)
>  
> +/* A transitive conflict is one where the first lock conflicts with
> + * the second lock, and any other lock that conflicts with the
> + * first lock, also conflicts with the second lock.
> + */
> +enum conflict {
> +     FL_NO_CONFLICT = 0,
> +     FL_CONFLICT,
> +     FL_TRANSITIVE_CONFLICT,
> +};
> +
>  static inline bool is_remote_lock(struct file *filp)
>  {
>       return likely(!(filp->f_path.dentry->d_sb->s_flags & SB_NOREMOTELOCK));
> @@ -612,6 +622,15 @@ static inline int locks_overlap(struct file_lock *fl1, 
> struct file_lock *fl2)
>               (fl2->fl_end >= fl1->fl_start));
>  }
>  
> +/* Check for transitive-overlap - true if any lock that overlaps
> + * the first lock must overlap the seconds
> + */
> +static inline bool locks_transitive_overlap(struct file_lock *fl1,
> +                                         struct file_lock *fl2)
> +{
> +     return (fl1->fl_start >= fl2->fl_start) &&
> +             (fl1->fl_end <= fl2->fl_end);
> +}
>  /*
>   * Check whether two locks have the same owner.
>   */
> @@ -793,47 +812,61 @@ locks_delete_lock_ctx(struct file_lock *fl, struct 
> list_head *dispose)
>  /* Determine if lock sys_fl blocks lock caller_fl. Common functionality
>   * checks for shared/exclusive status of overlapping locks.
>   */
> -static int locks_conflict(struct file_lock *caller_fl, struct file_lock 
> *sys_fl)
> +static enum conflict locks_conflict(struct file_lock *caller_fl,
> +                                 struct file_lock *sys_fl)
>  {
>       if (sys_fl->fl_type == F_WRLCK)
> -             return 1;
> +             return FL_TRANSITIVE_CONFLICT;
>       if (caller_fl->fl_type == F_WRLCK)
> -             return 1;
> -     return 0;
> +             return FL_CONFLICT;
> +     return FL_NO_CONFLICT;
>  }
>  
>  /* Determine if lock sys_fl blocks lock caller_fl. POSIX specific
>   * checking before calling the locks_conflict().
>   */
> -static int posix_locks_conflict(struct file_lock *caller_fl, struct 
> file_lock *sys_fl)
> +static enum conflict posix_locks_conflict(struct file_lock *caller_fl,
> +                                       struct file_lock *sys_fl)
>  {
>       /* POSIX locks owned by the same process do not conflict with
>        * each other.
>        */
>       if (posix_same_owner(caller_fl, sys_fl))
> -             return (0);
> +             return FL_NO_CONFLICT;
>  
>       /* Check whether they overlap */
>       if (!locks_overlap(caller_fl, sys_fl))
> -             return 0;
> +             return FL_NO_CONFLICT;
>  
> -     return (locks_conflict(caller_fl, sys_fl));
> +     switch (locks_conflict(caller_fl, sys_fl)) {
> +     default:
> +     case FL_NO_CONFLICT:
> +             return FL_NO_CONFLICT;
> +     case FL_CONFLICT:
> +             return FL_CONFLICT;

If I'm understanding the logic here and in locks_conflict correctly,
you're telling me that in the case where sys_fl is a read lock, and
caller_fl is a write lock, then any lock which conflicts with sys_fl
must conflict with caller_fl?  Or do I have that backwards?  It doesn't
sound right, in any case.

--b.

> +     case FL_TRANSITIVE_CONFLICT:
> +             if (locks_transitive_overlap(caller_fl, sys_fl))
> +                     return FL_TRANSITIVE_CONFLICT;
> +             else
> +                     return FL_CONFLICT;
> +     }
>  }
>  
>  /* Determine if lock sys_fl blocks lock caller_fl. FLOCK specific
>   * checking before calling the locks_conflict().
>   */
> -static int flock_locks_conflict(struct file_lock *caller_fl, struct 
> file_lock *sys_fl)
> +static enum conflict flock_locks_conflict(struct file_lock *caller_fl,
> +                                       struct file_lock *sys_fl)
>  {
>       /* FLOCK locks referring to the same filp do not conflict with
>        * each other.
>        */
>       if (caller_fl->fl_file == sys_fl->fl_file)
> -             return (0);
> +             return FL_NO_CONFLICT;
>       if ((caller_fl->fl_type & LOCK_MAND) || (sys_fl->fl_type & LOCK_MAND))
> -             return 0;
> +             return FL_NO_CONFLICT;
>  
> -     return (locks_conflict(caller_fl, sys_fl));
> +     return locks_conflict(caller_fl, sys_fl);
>  }
>  
>  void
> @@ -1435,12 +1468,13 @@ static void time_out_leases(struct inode *inode, 
> struct list_head *dispose)
>       }
>  }
>  
> -static bool leases_conflict(struct file_lock *lease, struct file_lock 
> *breaker)
> +static enum conflict leases_conflict(struct file_lock *lease,
> +                                  struct file_lock *breaker)
>  {
>       if ((breaker->fl_flags & FL_LAYOUT) != (lease->fl_flags & FL_LAYOUT))
> -             return false;
> +             return FL_NO_CONFLICT;
>       if ((breaker->fl_flags & FL_DELEG) && (lease->fl_flags & FL_LEASE))
> -             return false;
> +             return FL_NO_CONFLICT;
>       return locks_conflict(breaker, lease);
>  }
>  
> 

Reply via email to