Hi Andi,
On Thu, Oct 19, 2017 at 06:55:19AM -0700, Andi Kleen wrote:
> On Thu, Oct 19, 2017 at 12:59:14PM +0200, Milian Wolff wrote:
> > On Donnerstag, 19. Oktober 2017 00:41:04 CEST Andi Kleen wrote:
> > > Milian Wolff <milian.wo...@kdab.com> writes:
> > > > +static enum match_result match_address_dso(struct dso *left_dso, u64
> > > > left_ip, + struct dso
> > > > *right_dso, u64 right_ip)
> > > > +{
> > > > + if (left_dso == right_dso && left_ip == right_ip)
> > > > + return MATCH_EQ;
> > > > + else if (left_ip < right_ip)
> > > > + return MATCH_LT;
> > > > + else
> > > > + return MATCH_GT;
> > > > +}
> > >
> > > So why does only the first case check the dso? Does it not matter
> > > for the others?
> > >
> > > Either should be checked by none or by all.
> >
> > I don't see why it should be checked. It is only required to prevent two
> > addresses to be considered equal while they are not. So only the one check
> > is
> > required, otherwise we return either LT or GT.
>
> When the comparison is always in the same process (which I think
> is not the case) just checking the addresses is sufficient. If they are not
> then you
> always need to check the DSO and only compare inside the same DSO.
As far as I know, the node->ip is a relative address (inside a DSO).
So it should compare the dso as well even in the same process.
Thanks,
Namhyung
