Christoph Hellwig <h...@lst.de> wrote: > It's not a userspace ABI, so by defintion it does not break an > existing user program.
That's an invalid assumption. It is a de facto userspace ABI as it has been exposed in /usr/include/linux/uuid.h for some time. > If someone was using it they should be using uuid_t from libuuid instead, as > that gives them the routines to deal with it. Yes, they should - but that doesn't mean they do. David
