On Fri, Mar 31, 2017 at 03:41:18AM +0800, Yuyang Du wrote:
> > >
> > > p
> > > c2 = 1024 \Sum y^n
> > > n=1
> > >
> > > inf inf
> > > = 1024 ( \Sum y^n - \Sum y^n - y^0 )
> > > n=0 n=p
> >
> > It looks surprisingly kinda works :)
> >
> > > + c2 = LOAD_AVG_MAX - decay_load(LOAD_AVG_MAX, periods) - 1024;
> > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
> > But, I'm not sure this is what you want (just assume p==0).
> >
>
> Oh, what I meant is when p != 0, actually p>=1.
Right, note that we'll never get here with p==0. For p==1 we'll have
c2==0, and for p > 1 we'll have whatever section we wanted.
> And thinking about it for a while, it's really what you want, brilliant :)
Right, because:
inf inf inf
( \Sum y^n ) y^p = \Sum y^(n+p) = \Sum y^n
n=0 n=0 n=p
