arizona_poll_reg already returns ETIMEDOUT if we don't see the expected
register changes before the time out, so remove pointless local setting of
ETIMEDOUT.
Signed-off-by: Charles Keepax <ckee...@opensource.wolfsonmicro.com>
---
drivers/mfd/arizona-core.c | 8 ++------
1 file changed, 2 insertions(+), 6 deletions(-)
diff --git a/drivers/mfd/arizona-core.c b/drivers/mfd/arizona-core.c
index b6d4bc6..e00f577 100644
--- a/drivers/mfd/arizona-core.c
+++ b/drivers/mfd/arizona-core.c
@@ -342,10 +342,8 @@ static int arizona_enable_freerun_sysclk(struct arizona
*arizona,
ret = arizona_poll_reg(arizona, 25, ARIZONA_INTERRUPT_RAW_STATUS_5,
ARIZONA_FLL1_CLOCK_OK_STS,
ARIZONA_FLL1_CLOCK_OK_STS);
- if (ret) {
- ret = -ETIMEDOUT;
+ if (ret)
goto err_fll;
- }
ret = regmap_write(arizona->regmap, ARIZONA_SYSTEM_CLOCK_1, 0x0144);
if (ret) {
@@ -407,11 +405,9 @@ static int wm5102_apply_hardware_patch(struct arizona
*arizona)
ret = arizona_poll_reg(arizona, 5, ARIZONA_WRITE_SEQUENCER_CTRL_1,
ARIZONA_WSEQ_BUSY, 0);
- if (ret) {
+ if (ret)
regmap_write(arizona->regmap, ARIZONA_WRITE_SEQUENCER_CTRL_0,
ARIZONA_WSEQ_ABORT);
- ret = -ETIMEDOUT;
- }
err:
err = arizona_disable_freerun_sysclk(arizona, &state);
--
2.1.4
