On Thu, Aug 18, 2016 at 04:19:10PM +0800, zijun_hu wrote: > From: zijun_hu <zijun...@htc.com> > > for LP64 ABI, struct rb_node aligns at 8 bytes boundary due to > sizeof(long) == 8 normally, so 0x07 should be used to extract > node's parent rather than 0x03
Doesn't matter though, in practise. The remaining bits are always 0.
