From: Peter Hurley <pe...@hurleysoftware.com> Date: Sat, 27 Feb 2016 12:29:39 -0800
> Not really. softirq raised from interrupt context will always execute > on this cpu and not in ksoftirqd, unless load forces softirq loop abort. That guarantee never was specified. Or are you saying that by design, on a system under load, your UART will not function properly? Surely you don't mean that.
