Consider the following C++ program:
//: C12:OperatorOverloadingSyntax.cpp
// From Thinking in C++, 2nd Edition
// Available at http://www.BruceEckel.com
// (c) Bruce Eckel 2000
// Copyright notice in Copyright.txt
#include <iostream>
using namespace std;
class Integer {
int i;
public:
Integer(int ii) : i(ii) {}
const Integer
operator+(const Integer& rv) const {
cout << "operator+" << endl;
return Integer(i + rv.i);
}
Integer&
operator+=(const Integer& rv) {
cout << "operator+=" << endl;
i += rv.i;
return *this;
}
};
int main() {
cout << "built-in types:" << endl;
int i = 1, j = 2, k = 3;
k += i + j;
cout << "user-defined types:" << endl;
Integer ii(1), jj(2), kk(3);
kk += ii + jj;
} ///:~
Although I was able to compile it without warnings I do not understand:
1) What is the meaning of the first (left most) const in
const Integer operator+(const Integer& rv) ... ?
2) Isn't i a private member of Integer? Then how come it can be accessed with
an expression like rv.i?
--
-- Shaul Karl <[EMAIL PROTECTED]>
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