2014-11-24 6:56 GMT+01:00 Ted Lemon <mel...@fugue.com>:
> Hm, okay. So a (b c d) is wrong, and a( b c d) is right? Here both are ok; you simply omit to put any bar check: So a | (b c d) is wrong, and a( | b c d) is right. Cheers, Pierre
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