Pierre Perol-Schneider <pierre.schneider.pa...@gmail.com> writes:

> 2013/7/5 Pierre Perol-Schneider <pierre.schneider.pa...@gmail.com>
>
>>
>>
>>  kern = x-length*10* EXP[ [ [LN(0.13)/LN(20)]*LN(StaffSize) ] - LN(0.13) ]
>>
>
> Sorry again, i'm righting too fast
> so last shot :
>
> kern = x-length*10* EXP[ [ [LN(0.13)/LN(20)]*LN(StaffSize) ] + LN(0.13) ]
>
> this one should be the good one...

I have my doubts.  The exponential evaluates to
0.13 * Staffsize ** (ln(0.13)/ln(20))

-- 
David Kastrup


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