Pierre Perol-Schneider <pierre.schneider.pa...@gmail.com> writes: > 2013/7/5 Pierre Perol-Schneider <pierre.schneider.pa...@gmail.com> > >> >> >> kern = x-length*10* EXP[ [ [LN(0.13)/LN(20)]*LN(StaffSize) ] - LN(0.13) ] >> > > Sorry again, i'm righting too fast > so last shot : > > kern = x-length*10* EXP[ [ [LN(0.13)/LN(20)]*LN(StaffSize) ] + LN(0.13) ] > > this one should be the good one...
I have my doubts. The exponential evaluates to 0.13 * Staffsize ** (ln(0.13)/ln(20)) -- David Kastrup _______________________________________________ lilypond-user mailing list lilypond-user@gnu.org https://lists.gnu.org/mailman/listinfo/lilypond-user