Simply compiling and displaying the code you supplied gives 2 crochets and then 
2 pairs of beamed triplets.  It's not 6 notes beamed together.  I'd guess that 
you have over-ridden some beaming setting elsewhere in your score.

--
Phil Holmes


  ----- Original Message ----- 
  From: 胡海鹏 - Hu Haipeng 
  To: lilypond-user 
  Sent: Friday, September 24, 2010 4:25 PM
  Subject: visual problem on two triplets in 4/4 time


  Hello,
    My mother found a problem when I write continuous triplets. For example,
  \time 4/4 c'4 c' \times 2/3 { c'8 d' e' } \times 2/3 { f' g' a' }
  The two triplets are grouped like one sextupplet, but with two 3's. What's 
the problem? Is it a wrong practice in notation convention? Is it controlled by 
beam settings?
  Regards
  Haipeng


   



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