On 12/22/08 2:30 AM, "Stefan Thomas" <kontrapunktste...@googlemail.com>
wrote:
> Dear Lilypond-users,
> I trie to substitute the variable "zackigschnell' with "APZ', but
> without sucess.
> What is wrong with the following snippet?
>
> \version "2.11.60"
> \include "rhythmustest.ly"
> \new Staff { \APZ { c' d' e' f' } }
There's nothing wrong with the snippet.
The problem occurred in rhythmustest.ly.
You had the following:
zackigschnell = #(define-music-function (parser location music) (ly:music?)
#{ \makeRhythm $music "16. 32" #})
APZ = { \zackigschnell }
The way LilyPond substitution works, \zackigschnell needs to be followed by
a music expression. And in your definition of APZ, there is no music
expression following \zackigschnell. If you literally do the substitution,
you'll get
\new Staff { { \zackigschnell } {c' d' e' f' } }
and you can see that there is no music expression for \zackigschnell to
operator on.
If you literally want to just add a new name for a function, the way to do
it is with a scheme trick.
Simply add
#(define APZ zackigschnell)
and now APZ and zackigschnell are the same thing with two different names.
I've tried it on your code, and this works.
Good luck,
Carl
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