On Wed, Jul 2, 2008 at 11:04 PM, George_ <[EMAIL PROTECTED]> wrote: > > Basically, my problem is this - I want to typeset this chord: > <f g a b c d e>4. > > And this is what I get: > http://www.nabble.com/file/p18251902/1.jpg > > Because the notes of the chord are so close together and there are so many > of them, the dots all queue up. Surely there must be a way to eliminate all > the extra dots around the chord? I'm sure that even though it's not correct, > four or five dots are enough to get across to the player/reader that all the > notes are to be of dotted duration.
I found some published examples where there are fewer augmentation dots than note heads to avoid the problem that George describes. They are from piano reductions in choral pieces by Eric Whitacre: "When David Heard" and "Water Night" published by Walton Music. (You can hear excerpts at http://www.ericwhitacre.com/main.html) I don't know if the standard music engraving literature says anything about having more note heads than augmentation dots, but I think it the correct thing to do. Based on these examples, it looks like the algorithm could be Identify any groups of four or more adjacent note heads in a chord For each group: Find the second highest and second lowest note heads and place their augmentation dots in the spaces that would normally be chosen Add dots to any empty spaces between the first two dots Add one dot above and one dot below the existing ones Andrew
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