I'm struggling in my attempts at beaming two sixteenths in the middle of a triplet. Is this possible with automatic beaming, or must one result to beam counts?
I've attached an example showing my current output and my desired output;
code follows:
\paper{ ragged-right=##t }
\relative c'' {
\time 4/4
\times 2/3 { c8 c16 c c8 }
r4 r r
}
Thanks!
P.S. I'm using version 2.10.33.
<<attachment: Example.png>>
_______________________________________________ lilypond-user mailing list lilypond-user@gnu.org http://lists.gnu.org/mailman/listinfo/lilypond-user
