Thanks Mats and Nicolas !!!
That works perfect... thanx for the tip on \displayMusic... I will be
using it more often ;-)
cheers,
pietro
On 8/11/06, Nicolas Sceaux <[EMAIL PROTECTED]> wrote:
Mats Bengtsson <[EMAIL PROTECTED]> writes:
> Pietro Casella wrote:
>
>> Hi all,
>>
>> I'm trying to create something like this:
>>
>> blankbar = #(define-music-function (parser location x) (number?)
>> #{
>> \repeat unfold $x {s1}
>> #})
>>
>> \blankbar #56
> I'm afraid you have hit a limitation in the use of #{...#}. My
> recommendation
> is to change to plan B, which is described in the section on "Building
> complicated
> functions" in the manual for version 2.9.x.
Some more explanations:
#{ \repeat unfold $x {s1} #}
is equivalent to:
x=#3
\repeat unfold \x {s1}
which, if you try it, causes the syntax error you reported.
So, as Mats said, you have to do otherwise, but that's not too difficult
in that case.
\displayMusic \repeat unfold 3 {s1}
==>
(make-music
'UnfoldedRepeatedMusic
'elements
'()
'repeat-count
3
'element
(make-music
'SequentialMusic
'elements
(list (make-music
'EventChord
'elements
(list (make-music
'SkipEvent
'duration
(ly:make-duration 0 0 1 1)))))))
Search the "3" in the above expression: that's where you'll put the x
argument of your music function. You can even change the:
(make-music
'SequentialMusic
'elements
(list (make-music
'EventChord
'elements
(list (make-music
'SkipEvent
'duration
(ly:make-duration 0 0 1 1))))))
part with #{ s1 #} (which is what it means) to make the expression
shorter.
blankbar =
#(define-music-function (parser location x) (number?)
(make-music 'UnfoldedRepeatedMusic
'elements '()
'repeat-count x
'element #{ s1 #}))
\blankbar #56
simple!
nicolas
--
Pietro Casella
| + 351 91 60 60 339
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